PhpDev.App
php-mock/php-mock-phpunit

php-mock/php-mock-phpunit

Stars: 151

Forks: 16

Pull Requests: 27

Issues: 35

Watchers: 4

Last Updated: 2023-08-28 08:58:13

#mock #php #phpunit #builtin-functions #php-mock

Mock built-in PHP functions (e.g. time() or rand()) in PHPUnit.

License: Do What The F*ck You Want To Public License

Languages: PHP

.github/workflows/tests.yml

Mock PHP built-in functions with PHPUnit

This package integrates the function mock library PHP-Mock with PHPUnit.

Installation

Use Composer:

composer require --dev php-mock/php-mock-phpunit

Usage

PHP-Mock integrates with the trait PHPMock into your PHPUnit test case. This trait extends the framework by the method getFunctionMock(). With this method you can build a mock in the way you are used to build a PHPUnit mock:

namespace foo;

class BuiltinTest extends \PHPUnit\Framework\TestCase
{

    use \phpmock\phpunit\PHPMock;

    public function testTime()
    {
        $time = $this->getFunctionMock(__NAMESPACE__, "time");
        $time->expects($this->once())->willReturn(3);

        $this->assertEquals(3, time());
    }

    public function testExec()
    {
        $exec = $this->getFunctionMock(__NAMESPACE__, "exec");
        $exec->expects($this->once())->willReturnCallback(
            function ($command, &$output, &$return_var) {
                $this->assertEquals("foo", $command);
                $output = ["failure"];
                $return_var = 1;
            }
        );

        exec("foo", $output, $return_var);
        $this->assertEquals(["failure"], $output);
        $this->assertEquals(1, $return_var);
    }
}

There's no need to disable the mocked function. The PHPUnit integration does that for you.

Restrictions

This library comes with the same restrictions as the underlying php-mock:

  • Only unqualified function calls in a namespace context can be mocked. E.g. a call for time() in the namespace foo is mockable, a call for \time() is not.

  • The mock has to be defined before the first call to the unqualified function in the tested class. This is documented in Bug #68541. In most cases you can ignore this restriction. But if you happen to run into this issue you can call PHPMock::defineFunctionMock() before that first call (e.g. with @beforeClass). This would define a side effectless namespaced function. Another effective approach is running your test in an isolated process (e.g. with @runInSeparateProcess).

License and authors

This project is free and under the WTFPL. Responsable for this project is Markus Malkusch [email protected].

Donations

If you like this project and feel generous donate a few Bitcoins here: 1335STSwu9hST4vcMRppEPgENMHD2r1REK

OPEN ISSUES

See all

RELEASES

See all